Flat Fall sink rate

Discussion in 'San Diego Long Range fishing Reports' started by DennisV, Jun 24, 2018.

  1. Cubeye

    Cubeye I've posted enough I should edit this section

    Location:
    Los Angeles
    Name:
    Kub
    Boat:
    17' Gregor
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    I don't think guys that use spinners on a consistent basis for vertical jigging, crank the handle to engage the bail. They flip the bail by hand. This method is much quicker and eliminates line twist. Allowing the jig to fall freely, without any line tension, will allow the jig to fall as designed when using a spinner.

    Just the tension of a conventional spool turning affects the fall rate, and thus the action of the lure. Doesn't seem to matter how much 'Super Lube Oil' is applied to the bearings, there is still friction/inertia to overcome. When even the slightest tension is put on the line while falling, the "falling leaf" action is converted to a straight drop, with no action on the lure. This is why it falls faster.

    It would probably be best stop the lure, lift the rod tip, and let the lure "free fall".

    johndtuttle can explain it better than I can.
     
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  2. Luke

    Luke Uses alot of bait!

    Location:
    Laguna Niguel
    Name:
    Luke
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    At times last year the BF were marking deep, 250’ to 300’. On one trip they simply would not move out of that zone. Everyone was frustrated with trying to determine when to stop the Flatfall including me. After the trip at home working with my son Ryan we marked off 100’ in our backyard (we have a large backyard) and we then measured out the spectra with the topshots at 100’, 200’, and 300’. At each interval we put large back marks: 1 mark for 100’, 2 marks for 200’ and 3 marks for 300’. It was a pain to do it but we were no longer guessing.

    On the next trip when Jeff Markland said the fish were at 275’ I knew exactly when to stop and start the retrieve. And it worked, got one of only two BF on the boat. I am a believer and yes I do consider scope as part of the distance. With wind or breeze it is best to cast up swell so the first drop or two is exactly in the zone.

    As far as fall rate, just enough thumb pressure to keep the spool from over-rotating, let the Flatfall do it’s sinking thing.

    My two cents........

    Luke
     
    Last edited: Jun 26, 2018
  3. jeffreykooken

    jeffreykooken Jeff

    Location:
    Bakersfield, Ca
    Name:
    Jeff Kooken
    Boat:
    14' Aluninum
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    So, the jig stops moving, or line pools on the surface, what next? Hook set, or just retrieve line, or what? To eliminate the loss, if I don't "feel a strike", what am I looking for?
     
  4. RideHPD

    RideHPD Enthusiastic Idiot Rookie

    Location:
    Del Mar/Marina Del Rey, CA
    Name:
    Eric Marin
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    10' Model T
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    Rod pointed at the water, put it in gear and wind like hell, you have to get tension on them as fast as you can.
     
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  5. jeffreykooken

    jeffreykooken Jeff

    Location:
    Bakersfield, Ca
    Name:
    Jeff Kooken
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    Hook set?
     
  6. ripped

    ripped I've posted enough I should edit this section

    Location:
    Santa Barbara
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    Gary
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    Vagabond
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    If you wind into the fish it will hook itself. This ain’t Rolland Martin fishn’.
     
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  7. matta57

    matta57 hack

    Location:
    goleta
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    matt
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    good point, light thumb tension does make them drop faster with less flutter.
     
  8. matta57

    matta57 hack

    Location:
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    thats a good explanation, thank you.
     
  9. bparker1225

    bparker1225 Ocean Addiction

    Location:
    Leucadia/Los Zacatitos
    Name:
    Bill Parker
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    21' 6" Cabo-Cabo Bill
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    lthe net force (the vector sum of all forces acting on an object) is zero, then the velocity of the object is constant. Velocity is a vector quantity which expresses both the object's speed and the direction of its motion; therefore, the statement that the object's velocity is constant is a statement that both its speed and the direction of its motion are constant. Constant!

    This can be stated mathematically when the mass is a non-zero constant, as,

    [​IMG]
     
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  10. Tim Turis

    Tim Turis Well-Known "Member"

    Location:
    Atlanta GA
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    Tim Turis
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    I’m going to need a tutor...
     
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  11. Steve K

    Steve K Hey, I'm gettin' bit...

    Location:
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    Name:
    Steve
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    18' Bayrunner, but I like the American Angler and the Red Rooster III
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    Well, if the angle of the dangle equals the square root of the product of the drag coefficient divided by the wind speed...you might be successful! :)
     
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  12. TrophyAnchovy

    TrophyAnchovy Newbie

    Location:
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    James
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    This link might help some of you understand how it works
     
  13. DennisV

    DennisV Well-Known "Member"

    Location:
    Paloma, CA
    Name:
    Dennis Vagt
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    Just a NuCanoe Frontier now.
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    ein.jpg
     
  14. fyermn

    fyermn Member

    Location:
    Utah
    Name:
    Dan
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    LONG RANGE fishing
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    Tim; in the above equation--It is the lift verses the drag divided by the engine thrust of the engine on the right wing and the horsepower of the engine on the left wing. It is that simple.
     

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